3x^2-28x+53=-4

Solution for 3x^2-28x+53=-4 equation:

3x^2-28x+53=-4

We move all terms to the left:

3x^2-28x+53-(-4)=0

We add all the numbers together, and all the variables

3x^2-28x+57=0

a = 3; b = -28; c = +57;
Δ = b2-4ac
Δ = -282-4·3·57
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-10}{2*3}=\frac{18}{6}
=3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+10}{2*3}=\frac{38}{6}
=6+1/3
$